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5x^2=10^12
We move all terms to the left:
5x^2-(10^12)=0
We add all the numbers together, and all the variables
5x^2-1000000000000=0
a = 5; b = 0; c = -1000000000000;
Δ = b2-4ac
Δ = 02-4·5·(-1000000000000)
Δ = 20000000000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20000000000000}=\sqrt{4000000000000*5}=\sqrt{4000000000000}*\sqrt{5}=2000000\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2000000\sqrt{5}}{2*5}=\frac{0-2000000\sqrt{5}}{10} =-\frac{2000000\sqrt{5}}{10} =-200000\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2000000\sqrt{5}}{2*5}=\frac{0+2000000\sqrt{5}}{10} =\frac{2000000\sqrt{5}}{10} =200000\sqrt{5} $
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